stipud wrote:Thought of a good example... let's say you have a 500w amp playing a -0dB bass note for 1 second. For the sake of simplifying the argument, the amp is 50% efficient, so it requires 1000w to produce its rated power. 1000w at 14v is 1000/14=71.42 amps. This means to power the bass note for one second requires 71.42 coulombs of energy. If you were drawing only from a 1 farad capacitor (14 coulombs at 14v), with no external charge, it would be drained completely flat in 14/71.42 =0.196 seconds. Now this is assuming the amplifier would even run below 10v or so. If you assume that the amp turns off when the voltage sags below 10v, then you only have 4 coulombs of power available, which means it would be drained to 10v in 4/71.42 = 0.056 seconds.
So for powering an amp, a capacitor is utterly useless. But for filtering microscopic ripple in D/C there is nothing better.
Stipud, I think your math here is good, but I think there may be a bit more to the story. I know I don't have the math to fully explain this, but I am going to do my best to use what logic I have. I also notice you mention "no external charge" but that has to be considered. A cap is not a battery, that is for certain.
You have three sources for energy in your stereo, the alternator, the battery and the capacitor.
The alternator has a maximum quantity of current it can deliver, it is say 75A for a common one (maybe there are larger, I really don't keep up on it).
The battery is capable of the most current, maybe 1000A for a short period of time.
The cap is capable of very little storage, but delivers it nearly instantly.
When a bass note hits, the cap starts to drain before the battery, but the battery is still feeding it, and it is feeding it based on the size of the power wire and its own internal current limitations.
This is either a calculus problem or even a differential equation involving a formula for the current flow into the cap vs the current flow out of the cap. Now if an amp shuts down at say 10V of input voltage, the cap will delay the time for the voltage to drop to 10V vs without the cap. This delay is significant enough to keep the amp on in many cases.
A larger alternator will delay the drop from 14.4V down to 12.6V at the battery. So it will improve the chain as well.
A larger battery or more batteries might only help if the power wire is large enough, which generally is one of the biggest issues the person is starting with, too small a power wire.
I know you guys like to make the point a cap is great for filtering DC ripple, but I don't think a single car audio salesman would sell one based on that point. They probably would not even understand that point. They sell them as a Band-Aid to someone with other installation issues, and if the Band-Aid stops the bleeding, the customer is happy.
Got "schooled" by member shawn k on May 10th, 2011...
No longer really "in tune" with the audio industry, and probably have not been for some time.
Hands down the forum's most ignorant member...
Don't even know what Ohm's law is...