How do you measure the output of a line driver?
How do you measure the output of a line driver?
Maybe I am doing this all wrong but I am puting one measuring thingy off a dmm in each out put channel. Im guessing this is wrong.
Are you suppose to measure each channel alone, if this is the case, is each channel suppose to give out 4 volts on a 4 volt preout or 2 volts per channel to make 4 volts total? This is for both a sub output and for my fronts
Are you suppose to measure each channel alone, if this is the case, is each channel suppose to give out 4 volts on a 4 volt preout or 2 volts per channel to make 4 volts total? This is for both a sub output and for my fronts
Right but im not measuring a deck, im measuring the output off a line driver.Eric D wrote:O, and you do measure each channel separate. Each one should do 4V.
In my experience though, none of these things ever seem to do what the manufacturer rates them at. A 4V deck for example which I tested was only 2V.
One deck rated at 2.2V, was 2.2V.
So for measuring, one line inside the female part and one on the outside of it?
Right, but a deck and a line driver are no different.Capital_M wrote:Right but im not measuring a deck, im measuring the output off a line driver.Eric D wrote:O, and you do measure each channel separate. Each one should do 4V.
In my experience though, none of these things ever seem to do what the manufacturer rates them at. A 4V deck for example which I tested was only 2V.
One deck rated at 2.2V, was 2.2V.
So for measuring, one line inside the female part and one on the outside of it?
Yes, the inside of the RCA is the positive (+), and the outside is the negative (-).
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If he does that, I think he will blow a speaker, or maybe damage the amp.Francious70 wrote:Connect the line drive to an amp, and turn the amps gain to 0, then measure across on channel or bridged, and turn the line driver up until the voltage stops going up, then back it down a hair.
Once you hit clipping, if you keep turning the gain up, the voltage still goes up. The sine wave just becomes more and more of a square wave.
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Oh, for real? I figured that it would have a limit. Like having an 8V sine wave, if you push it into clipping, you're not going to be making the amplitude any greater. So I figured the voltage would cap.Eric D wrote:If he does that, I think he will blow a speaker, or maybe damage the amp.Francious70 wrote:Connect the line drive to an amp, and turn the amps gain to 0, then measure across on channel or bridged, and turn the line driver up until the voltage stops going up, then back it down a hair.
Once you hit clipping, if you keep turning the gain up, the voltage still goes up. The sine wave just becomes more and more of a square wave.
Boomshackalacka
If you have an amp for example with a since wave at max unclipped and it is lets say 10V, you can get more out of it.
I always get the math wrong, but it involves the square root of 2 to convert from RMS.
I am guessing in the case of the 10V amp, it would go up to 14V.
Well, 10V is 25W into 4 ohms, whereas 14V is 49W. That is twice the power, but maximum clipping.
I always get the math wrong, but it involves the square root of 2 to convert from RMS.
I am guessing in the case of the 10V amp, it would go up to 14V.
Well, 10V is 25W into 4 ohms, whereas 14V is 49W. That is twice the power, but maximum clipping.
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The gain matches the output of the deck to the input of the amp, but turning it up effectively increases the output voltage of the amp.
As the output voltage goes up, the load (speaker) will draw more current from the amp.
I could explain this a whole lot better if I took some photos of an oscilloscope measuring these things.
As the output voltage goes up, the load (speaker) will draw more current from the amp.
I could explain this a whole lot better if I took some photos of an oscilloscope measuring these things.
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This makes sense to me.Eric D wrote:The gain matches the output of the deck to the input of the amp, but turning it up effectively increases the output voltage of the amp.
As the output voltage goes up, the load (speaker) will draw more current from the amp.
I could explain this a whole lot better if I took some photos of an oscilloscope measuring these things.
So basically, as you throw more voltage to a load (speaker) it will naturally want to draw more current as well.
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